If the normal force applied during defibrillation is 100 N with an area of 0.005 m², what is the pressure exerted on the chest?

• A. 5 kPa
• B. 10 kPa
• C. 15 kPa
• D. 20 kPa

Answer: (D)

To determine the pressure exerted on the chest during defibrillation, we can use the formula for pressure, which is defined as force divided by area:

[

\text{Pressure} = \frac{\text{Force}}{\text{Area}}

]

In this case, the force exerted is 100 N and the area is 0.005 m². Plugging these values into the formula gives:

[

\text{Pressure} = \frac{100 , \text{N}}{0.005 , \text{m}²}

]

Calculating this results in:

[

\text{Pressure} = 20000 , \text{N/m}² = 20000 , \text{Pa} = 20 , \text{kPa}

]

Therefore, the pressure exerted on the chest during defibrillation is 20 kPa, which corresponds to the correct answer. This value represents how force is distributed over a given area, and higher pressure values can signify either greater force or smaller areas being utilized. In medical contexts, such calculations are critical for ensuring that the necessary force is applied effectively to achieve desired physiological responses.